2/y+5/2=4-2/3y

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Solution for 2/y+5/2=4-2/3y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2/y+5/2 = 4-((2/3)*y) // - 4-((2/3)*y)

(2/3)*y+2/y+5/2-4 = 0

2/3*y^1+2*y^-1-3/2*y^0 = 0

(2/3*y^2-3/2*y^1+2*y^0)/(y^1) = 0 // * y^2

y^1*(2/3*y^2-3/2*y^1+2*y^0) = 0

y^1

(2/3)*y^2+(-3/2)*y+2 = 0

(2/3)*y^2+(-3/2)*y+2 = 0

DELTA = (-3/2)^2-(2*4*(2/3))

DELTA = -37/12

DELTA < 0

y in { } 

y belongs to the empty set

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