2/y+5/3=26/3-y

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Solution for 2/y+5/3=26/3-y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2/y+5/3 = 26/3-y // - 26/3-y

y+2/y+5/3-(26/3) = 0

y+2/y+5/3-26/3 = 0

1*y^1+2*y^-1-7*y^0 = 0

(1*y^2-7*y^1+2*y^0)/(y^1) = 0 // * y^2

y^1*(1*y^2-7*y^1+2*y^0) = 0

y^1

y^2-7*y+2 = 0

y^2-7*y+2 = 0

DELTA = (-7)^2-(1*2*4)

DELTA = 41

DELTA > 0

y = (41^(1/2)+7)/(1*2) or y = (7-41^(1/2))/(1*2)

y = (41^(1/2)+7)/2 or y = (7-41^(1/2))/2

y in { (7-41^(1/2))/2, (41^(1/2)+7)/2} 

y in { (7-41^(1/2))/2, (41^(1/2)+7)/2 }

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