2/y+7/2y=6/5

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Solution for 2/y+7/2y=6/5 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(7/2)*y+2/y = 6/5 // - 6/5

(7/2)*y+2/y-(6/5) = 0

(7/2)*y+2/y-6/5 = 0

7/2*y^1+2*y^-1-6/5*y^0 = 0

(7/2*y^2-6/5*y^1+2*y^0)/(y^1) = 0 // * y^2

y^1*(7/2*y^2-6/5*y^1+2*y^0) = 0

y^1

(7/2)*y^2+(-6/5)*y+2 = 0

(7/2)*y^2+(-6/5)*y+2 = 0

DELTA = (-6/5)^2-(2*4*(7/2))

DELTA = -664/25

DELTA < 0

y in { } 

y belongs to the empty set

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