2/y-4/(y-4)=2/3

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Solution for 2/y-4/(y-4)=2/3 equation: 



2/y-4/(y-4)=2/3

We move all terms to the left:

2/y-4/(y-4)-(2/3)=0



Domain of the equation: y!=0

y∈R





Domain of the equation: (y-4)!=0

We move all terms containing y to the left, all other terms to the right

y!=4

y∈R



We add all the numbers together, and all the variables

2/y-4/(y-4)-(+2/3)=0

We get rid of parentheses

2/y-4/(y-4)-2/3=0

We calculate fractions


(-2y^2*()/(3y^2-12y)+(6y-24)/(3y^2-12y)+(-36y)/(3y^2-12y)=0



We calculate terms in parentheses: +(-2y^2*()/(3y^2-12y)+(6y-24)/(3y^2-12y)+(-36y)/(3y^2-12y), so:

-2y^2*()/(3y^2-12y)+(6y-24)/(3y^2-12y)+(-36y)/(3y^2-12y

We calculate fractions


(-2y^2*()+(6y-24)*(3y^2-12y)/((3y^2-12y)*(3y^2-12y)+((-36y)*(3y^2-12y))/((3y^2-12y)*(3y^2-12y)



We calculate terms in parentheses: +(-2y^2*()+(6y-24)*(3y^2-12y)/((3y^2-12y)*(3y^2-12y)+((-36y)*(3y^2-12y))/((3y^2-12y)*(3y^2-12y), so:

-2y^2*()+(6y-24)*(3y^2-12y)/((3y^2-12y)*(3y^2-12y)+((-36y)*(3y^2-12y))/((3y^2-12y)*(3y^2-12y

We can not solve this equation

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