2/y-6=-5/2y-12

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Solution for 2/y-6=-5/2y-12 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

2/y-6 = (-5/2)*y-12 // - (-5/2)*y-12

2/y-((-5/2)*y)-6+12 = 0

(5/2)*y+2/y-6+12 = 0

5/2*y^1+2*y^-1+6*y^0 = 0

(5/2*y^2+6*y^1+2*y^0)/(y^1) = 0 // * y^2

y^1*(5/2*y^2+6*y^1+2*y^0) = 0

y^1

(5/2)*y^2+6*y+2 = 0

(5/2)*y^2+6*y+2 = 0

DELTA = 6^2-(2*4*(5/2))

DELTA = 16

DELTA > 0

y = (16^(1/2)-6)/(2*(5/2)) or y = (-16^(1/2)-6)/(2*(5/2))

y = -2/5 or y = -2

y in { -2, -2/5} 

y in { -2, -2/5 }

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