2/z-5=z/0.5(2)+7

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Solution for 2/z-5=z/0.5(2)+7 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

2/z-5 = 2*(z/0.5)+7 // - 2*(z/0.5)+7

2/z-(2*(z/0.5))-7-5 = 0

2/z-4*z-7-5 = 0

2*z^-1-4*z^1-12*z^0 = 0

(2*z^0-4*z^2-12*z^1)/(z^1) = 0 // * z^2

z^1*(2*z^0-4*z^2-12*z^1) = 0

z^1

2-4*z^2-12*z = 0

2-4*z^2-12*z = 0

DELTA = (-12)^2-(-4*2*4)

DELTA = 176

DELTA > 0

z = (176^(1/2)+12)/(-4*2) or z = (12-176^(1/2))/(-4*2)

z = (4*11^(1/2)+12)/(-8) or z = (12-4*11^(1/2))/(-8)

z in { (4*11^(1/2)+12)/(-8), (12-4*11^(1/2))/(-8)} 

z in { (4*11^(1/2)+12)/(-8), (12-4*11^(1/2))/(-8) }

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