2/z-5=z/50+7

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Solution for 2/z-5=z/50+7 equation:


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

2/z-5 = z/50+7 // - z/50+7

2/z-(z/50)-7-5 = 0

2*z^-1-1/50*z^1-12*z^0 = 0

(2*z^0-1/50*z^2-12*z^1)/(z^1) = 0 // * z^2

z^1*(2*z^0-1/50*z^2-12*z^1) = 0

z^1

(-1/50)*z^2-12*z+2 = 0

(-1/50)*z^2-12*z+2 = 0

DELTA = (-12)^2-(2*4*(-1/50))

DELTA = 3604/25

DELTA > 0

z = ((3604/25)^(1/2)+12)/(2*(-1/50)) or z = (12-(3604/25)^(1/2))/(2*(-1/50))

z = -25*((3604/25)^(1/2)+12) or z = -25*(12-(3604/25)^(1/2))

z in { -25*((3604/25)^(1/2)+12), -25*(12-(3604/25)^(1/2))}

z in { -25*((3604/25)^(1/2)+12), -25*(12-(3604/25)^(1/2)) }

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