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20((250-25y)/20)+25y=250
We move all terms to the left:
20((250-25y)/20)+25y-(250)=0
We add all the numbers together, and all the variables
20((-25y+250)/20)+25y-250=0
We add all the numbers together, and all the variables
25y+20((-25y+250)/20)-250=0
We multiply all the terms by the denominator
25y*20)+20((-25y+250)-250*20)=0
We add all the numbers together, and all the variables
25y*20)+20((-25y+250)=0
Wy multiply elements
500y^2=0
a = 500; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·500·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{1000}=0$
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