20(-6x+12)=31(x-2)

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Solution for 20(-6x+12)=31(x-2) equation: 



20(-6x+12)=31(x-2)

We move all terms to the left:

20(-6x+12)-(31(x-2))=0

We multiply parentheses

-120x-(31(x-2))+240=0



We calculate terms in parentheses: -(31(x-2)), so:

31(x-2)

We multiply parentheses

31x-62

Back to the equation:

-(31x-62)



We get rid of parentheses

-120x-31x+62+240=0

We add all the numbers together, and all the variables

-151x+302=0

We move all terms containing x to the left, all other terms to the right

-151x=-302

x=-302/-151

x=+2

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