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20(0.3-x)(0.5-x)=0.6-x
We move all terms to the left:
20(0.3-x)(0.5-x)-(0.6-x)=0
We add all the numbers together, and all the variables
20(-1x+0.3)(-1x+0.5)-(-1x+0.6)=0
We get rid of parentheses
20(-1x+0.3)(-1x+0.5)+1x-0.6=0
We multiply parentheses ..
20(+x^2-0.5x-0.3x+0.15)+1x-0.6=0
We add all the numbers together, and all the variables
20(+x^2-0.5x-0.3x+0.15)+x-0.6=0
We multiply parentheses
20x^2+0x+0x+x+3-0.6=0
We add all the numbers together, and all the variables
20x^2+3x+2.4=0
a = 20; b = 3; c = +2.4;
Δ = b2-4ac
Δ = 32-4·20·2.4
Δ = -183
Delta is less than zero, so there is no solution for the equation
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