20(10+2f)=80

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Solution for 20(10+2f)=80 equation: 



20(10+2f)=80

We move all terms to the left:

20(10+2f)-(80)=0

We add all the numbers together, and all the variables

20(2f+10)-80=0

We multiply parentheses

40f+200-80=0

We add all the numbers together, and all the variables

40f+120=0

We move all terms containing f to the left, all other terms to the right

40f=-120

f=-120/40

f=-3

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