20(13x-50)=10(9-15x)+8(5-x)

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Solution for 20(13x-50)=10(9-15x)+8(5-x) equation: 



20(13x-50)=10(9-15x)+8(5-x)

We move all terms to the left:

20(13x-50)-(10(9-15x)+8(5-x))=0

We add all the numbers together, and all the variables

20(13x-50)-(10(-15x+9)+8(-1x+5))=0

We multiply parentheses

260x-(10(-15x+9)+8(-1x+5))-1000=0



We calculate terms in parentheses: -(10(-15x+9)+8(-1x+5)), so:

10(-15x+9)+8(-1x+5)

We multiply parentheses

-150x-8x+90+40

We add all the numbers together, and all the variables

-158x+130

Back to the equation:

-(-158x+130)



We get rid of parentheses

260x+158x-130-1000=0

We add all the numbers together, and all the variables

418x-1130=0

We move all terms containing x to the left, all other terms to the right

418x=1130

x=1130/418

x=2+147/209

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