20(2c+1)-19(2c+1)=

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Solution for 20(2c+1)-19(2c+1)= equation:


Simplifying
20(2c + 1) + -19(2c + 1) = 0

Reorder the terms:
20(1 + 2c) + -19(2c + 1) = 0
(1 * 20 + 2c * 20) + -19(2c + 1) = 0
(20 + 40c) + -19(2c + 1) = 0

Reorder the terms:
20 + 40c + -19(1 + 2c) = 0
20 + 40c + (1 * -19 + 2c * -19) = 0
20 + 40c + (-19 + -38c) = 0

Reorder the terms:
20 + -19 + 40c + -38c = 0

Combine like terms: 20 + -19 = 1
1 + 40c + -38c = 0

Combine like terms: 40c + -38c = 2c
1 + 2c = 0

Solving
1 + 2c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2c = 0 + -1
2c = 0 + -1

Combine like terms: 0 + -1 = -1
2c = -1

Divide each side by '2'.
c = -0.5

Simplifying
c = -0.5

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