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20(2x-9)=10(9)
We move all terms to the left:
20(2x-9)-(10(9))=0
determiningTheFunctionDomain 20(2x-9)-109=0
We multiply parentheses
40x-180-109=0
We add all the numbers together, and all the variables
40x-289=0
We move all terms containing x to the left, all other terms to the right
40x=289
x=289/40
x=7+9/40
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