20(3+a)=(7+1/6)20

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Solution for 20(3+a)=(7+1/6)20 equation: 



20(3+a)=(7+1/6)20

We move all terms to the left:

20(3+a)-((7+1/6)20)=0

We add all the numbers together, and all the variables

20(a+3)-((1/6+7)20)=0

We multiply parentheses

20a+60-((1/6+7)20)=0

We multiply all the terms by the denominator


20a*6+7)20)+60*6+7)20)-((1=0

We add all the numbers together, and all the variables

20a*6=0

Wy multiply elements

120a=0

a=0/120

a=0

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