20(3+s)=120

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Solution for 20(3+s)=120 equation: 



20(3+s)=120

We move all terms to the left:

20(3+s)-(120)=0

We add all the numbers together, and all the variables

20(s+3)-120=0

We multiply parentheses

20s+60-120=0

We add all the numbers together, and all the variables

20s-60=0

We move all terms containing s to the left, all other terms to the right

20s=60

s=60/20

s=3

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