20(3-x)=2(8+x)

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Solution for 20(3-x)=2(8+x) equation: 



20(3-x)=2(8+x)

We move all terms to the left:

20(3-x)-(2(8+x))=0

We add all the numbers together, and all the variables

20(-1x+3)-(2(x+8))=0

We multiply parentheses

-20x-(2(x+8))+60=0



We calculate terms in parentheses: -(2(x+8)), so:

2(x+8)

We multiply parentheses

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

-20x-2x-16+60=0

We add all the numbers together, and all the variables

-22x+44=0

We move all terms containing x to the left, all other terms to the right

-22x=-44

x=-44/-22

x=+2

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