20(3x+1)=32

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Solution for 20(3x+1)=32 equation: 



20(3x+1)=32

We move all terms to the left:

20(3x+1)-(32)=0

We multiply parentheses

60x+20-32=0

We add all the numbers together, and all the variables

60x-12=0

We move all terms containing x to the left, all other terms to the right

60x=12

x=12/60

x=1/5

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