20(3x+2)=8(x+1)

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Solution for 20(3x+2)=8(x+1) equation: 



20(3x+2)=8(x+1)

We move all terms to the left:

20(3x+2)-(8(x+1))=0

We multiply parentheses

60x-(8(x+1))+40=0



We calculate terms in parentheses: -(8(x+1)), so:

8(x+1)

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We get rid of parentheses

60x-8x-8+40=0

We add all the numbers together, and all the variables

52x+32=0

We move all terms containing x to the left, all other terms to the right

52x=-32

x=-32/52

x=-8/13

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