20(3x-7)+15(2x+5)=12(14-x)

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Solution for 20(3x-7)+15(2x+5)=12(14-x) equation: 



20(3x-7)+15(2x+5)=12(14-x)

We move all terms to the left:

20(3x-7)+15(2x+5)-(12(14-x))=0

We add all the numbers together, and all the variables

20(3x-7)+15(2x+5)-(12(-1x+14))=0

We multiply parentheses

60x+30x-(12(-1x+14))-140+75=0



We calculate terms in parentheses: -(12(-1x+14)), so:

12(-1x+14)

We multiply parentheses

-12x+168

Back to the equation:

-(-12x+168)



We add all the numbers together, and all the variables

90x-(-12x+168)-65=0

We get rid of parentheses

90x+12x-168-65=0

We add all the numbers together, and all the variables

102x-233=0

We move all terms containing x to the left, all other terms to the right

102x=233

x=233/102

x=2+29/102

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