20(63-22x)=10x-36

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Solution for 20(63-22x)=10x-36 equation: 



20(63-22x)=10x-36

We move all terms to the left:

20(63-22x)-(10x-36)=0

We add all the numbers together, and all the variables

20(-22x+63)-(10x-36)=0

We multiply parentheses

-440x-(10x-36)+1260=0

We get rid of parentheses

-440x-10x+36+1260=0

We add all the numbers together, and all the variables

-450x+1296=0

We move all terms containing x to the left, all other terms to the right

-450x=-1296

x=-1296/-450

x=2+22/25

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