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20(7-d)11d=113
We move all terms to the left:
20(7-d)11d-(113)=0
We add all the numbers together, and all the variables
20(-1d+7)11d-113=0
We multiply parentheses
-220d^2+1540d-113=0
a = -220; b = 1540; c = -113;
Δ = b2-4ac
Δ = 15402-4·(-220)·(-113)
Δ = 2272160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2272160}=\sqrt{16*142010}=\sqrt{16}*\sqrt{142010}=4\sqrt{142010}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1540)-4\sqrt{142010}}{2*-220}=\frac{-1540-4\sqrt{142010}}{-440} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1540)+4\sqrt{142010}}{2*-220}=\frac{-1540+4\sqrt{142010}}{-440} $
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