20(7y+4)-18(3y+4)-5=25(y+5)

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Solution for 20(7y+4)-18(3y+4)-5=25(y+5) equation: 



20(7y+4)-18(3y+4)-5=25(y+5)

We move all terms to the left:

20(7y+4)-18(3y+4)-5-(25(y+5))=0

We multiply parentheses

140y-54y-(25(y+5))+80-72-5=0



We calculate terms in parentheses: -(25(y+5)), so:

25(y+5)

We multiply parentheses

25y+125

Back to the equation:

-(25y+125)



We add all the numbers together, and all the variables

86y-(25y+125)+3=0

We get rid of parentheses

86y-25y-125+3=0

We add all the numbers together, and all the variables

61y-122=0

We move all terms containing y to the left, all other terms to the right

61y=122

y=122/61

y=2

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