20(n+2)=4(10+5n)

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Solution for 20(n+2)=4(10+5n) equation:


Simplifying
20(n + 2) = 4(10 + 5n)

Reorder the terms:
20(2 + n) = 4(10 + 5n)
(2 * 20 + n * 20) = 4(10 + 5n)
(40 + 20n) = 4(10 + 5n)
40 + 20n = (10 * 4 + 5n * 4)
40 + 20n = (40 + 20n)

Add '-40' to each side of the equation.
40 + -40 + 20n = 40 + -40 + 20n

Combine like terms: 40 + -40 = 0
0 + 20n = 40 + -40 + 20n
20n = 40 + -40 + 20n

Combine like terms: 40 + -40 = 0
20n = 0 + 20n
20n = 20n

Add '-20n' to each side of the equation.
20n + -20n = 20n + -20n

Combine like terms: 20n + -20n = 0
0 = 20n + -20n

Combine like terms: 20n + -20n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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