20(n+5)=4(25+5n)

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Solution for 20(n+5)=4(25+5n) equation:


Simplifying
20(n + 5) = 4(25 + 5n)

Reorder the terms:
20(5 + n) = 4(25 + 5n)
(5 * 20 + n * 20) = 4(25 + 5n)
(100 + 20n) = 4(25 + 5n)
100 + 20n = (25 * 4 + 5n * 4)
100 + 20n = (100 + 20n)

Add '-100' to each side of the equation.
100 + -100 + 20n = 100 + -100 + 20n

Combine like terms: 100 + -100 = 0
0 + 20n = 100 + -100 + 20n
20n = 100 + -100 + 20n

Combine like terms: 100 + -100 = 0
20n = 0 + 20n
20n = 20n

Add '-20n' to each side of the equation.
20n + -20n = 20n + -20n

Combine like terms: 20n + -20n = 0
0 = 20n + -20n

Combine like terms: 20n + -20n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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