20(n+7)=4(35+5n)

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Solution for 20(n+7)=4(35+5n) equation:


Simplifying
20(n + 7) = 4(35 + 5n)

Reorder the terms:
20(7 + n) = 4(35 + 5n)
(7 * 20 + n * 20) = 4(35 + 5n)
(140 + 20n) = 4(35 + 5n)
140 + 20n = (35 * 4 + 5n * 4)
140 + 20n = (140 + 20n)

Add '-140' to each side of the equation.
140 + -140 + 20n = 140 + -140 + 20n

Combine like terms: 140 + -140 = 0
0 + 20n = 140 + -140 + 20n
20n = 140 + -140 + 20n

Combine like terms: 140 + -140 = 0
20n = 0 + 20n
20n = 20n

Add '-20n' to each side of the equation.
20n + -20n = 20n + -20n

Combine like terms: 20n + -20n = 0
0 = 20n + -20n

Combine like terms: 20n + -20n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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