20(n-4)-12(n-5)=n-6

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Solution for 20(n-4)-12(n-5)=n-6 equation: 



20(n-4)-12(n-5)=n-6

We move all terms to the left:

20(n-4)-12(n-5)-(n-6)=0

We multiply parentheses

20n-12n-(n-6)-80+60=0

We get rid of parentheses

20n-12n-n+6-80+60=0

We add all the numbers together, and all the variables

7n-14=0

We move all terms containing n to the left, all other terms to the right

7n=14

n=14/7

n=2

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