20(v+2)-4v=4(4v+3)-19

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Solution for 20(v+2)-4v=4(4v+3)-19 equation: 



20(v+2)-4v=4(4v+3)-19

We move all terms to the left:

20(v+2)-4v-(4(4v+3)-19)=0

We add all the numbers together, and all the variables

-4v+20(v+2)-(4(4v+3)-19)=0

We multiply parentheses

-4v+20v-(4(4v+3)-19)+40=0



We calculate terms in parentheses: -(4(4v+3)-19), so:

4(4v+3)-19

We multiply parentheses

16v+12-19

We add all the numbers together, and all the variables

16v-7

Back to the equation:

-(16v-7)



We add all the numbers together, and all the variables

16v-(16v-7)+40=0

We get rid of parentheses

16v-16v+7+40=0

We add all the numbers together, and all the variables

47!=0

There is no solution for this equation

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