20(x+2)-12(x+1)=15(x-3)-60

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Solution for 20(x+2)-12(x+1)=15(x-3)-60 equation: 



20(x+2)-12(x+1)=15(x-3)-60

We move all terms to the left:

20(x+2)-12(x+1)-(15(x-3)-60)=0

We multiply parentheses

20x-12x-(15(x-3)-60)+40-12=0



We calculate terms in parentheses: -(15(x-3)-60), so:

15(x-3)-60

We multiply parentheses

15x-45-60

We add all the numbers together, and all the variables

15x-105

Back to the equation:

-(15x-105)



We add all the numbers together, and all the variables

8x-(15x-105)+28=0

We get rid of parentheses

8x-15x+105+28=0

We add all the numbers together, and all the variables

-7x+133=0

We move all terms containing x to the left, all other terms to the right

-7x=-133

x=-133/-7

x=+19

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