20(x+2)=5x+10=4(5x+10)+31

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Solution for 20(x+2)=5x+10=4(5x+10)+31 equation: 



20(x+2)=5x+10=4(5x+10)+31

We move all terms to the left:

20(x+2)-(5x+10)=0

We multiply parentheses

20x-(5x+10)+40=0

We get rid of parentheses

20x-5x-10+40=0

We add all the numbers together, and all the variables

15x+30=0

We move all terms containing x to the left, all other terms to the right

15x=-30

x=-30/15

x=-2

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