20(x+3)-4=56

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Solution for 20(x+3)-4=56 equation: 



20(x+3)-4=56

We move all terms to the left:

20(x+3)-4-(56)=0

We add all the numbers together, and all the variables

20(x+3)-60=0

We multiply parentheses

20x+60-60=0

We add all the numbers together, and all the variables

20x=0

x=0/20

x=0

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