20(x-1)+3(x-2)=4(2-x)+6

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Solution for 20(x-1)+3(x-2)=4(2-x)+6 equation: 



20(x-1)+3(x-2)=4(2-x)+6

We move all terms to the left:

20(x-1)+3(x-2)-(4(2-x)+6)=0

We add all the numbers together, and all the variables

20(x-1)+3(x-2)-(4(-1x+2)+6)=0

We multiply parentheses

20x+3x-(4(-1x+2)+6)-20-6=0



We calculate terms in parentheses: -(4(-1x+2)+6), so:

4(-1x+2)+6

We multiply parentheses

-4x+8+6

We add all the numbers together, and all the variables

-4x+14

Back to the equation:

-(-4x+14)



We add all the numbers together, and all the variables

23x-(-4x+14)-26=0

We get rid of parentheses

23x+4x-14-26=0

We add all the numbers together, and all the variables

27x-40=0

We move all terms containing x to the left, all other terms to the right

27x=40

x=40/27

x=1+13/27

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