20(x-2)+4=12(x+6)-6

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Solution for 20(x-2)+4=12(x+6)-6 equation: 



20(x-2)+4=12(x+6)-6

We move all terms to the left:

20(x-2)+4-(12(x+6)-6)=0

We multiply parentheses

20x-(12(x+6)-6)-40+4=0



We calculate terms in parentheses: -(12(x+6)-6), so:

12(x+6)-6

We multiply parentheses

12x+72-6

We add all the numbers together, and all the variables

12x+66

Back to the equation:

-(12x+66)



We add all the numbers together, and all the variables

20x-(12x+66)-36=0

We get rid of parentheses

20x-12x-66-36=0

We add all the numbers together, and all the variables

8x-102=0

We move all terms containing x to the left, all other terms to the right

8x=102

x=102/8

x=12+3/4

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