20(x-y)-10(3x-q)=

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Solution for 20(x-y)-10(3x-q)= equation:


Simplifying
20(x + -1y) + -10(3x + -1q) = 0
(x * 20 + -1y * 20) + -10(3x + -1q) = 0
(20x + -20y) + -10(3x + -1q) = 0

Reorder the terms:
20x + -20y + -10(-1q + 3x) = 0
20x + -20y + (-1q * -10 + 3x * -10) = 0
20x + -20y + (10q + -30x) = 0

Reorder the terms:
10q + 20x + -30x + -20y = 0

Combine like terms: 20x + -30x = -10x
10q + -10x + -20y = 0

Solving
10q + -10x + -20y = 0

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '10x' to each side of the equation.
10q + -10x + 10x + -20y = 0 + 10x

Combine like terms: -10x + 10x = 0
10q + 0 + -20y = 0 + 10x
10q + -20y = 0 + 10x
Remove the zero:
10q + -20y = 10x

Add '20y' to each side of the equation.
10q + -20y + 20y = 10x + 20y

Combine like terms: -20y + 20y = 0
10q + 0 = 10x + 20y
10q = 10x + 20y

Divide each side by '10'.
q = x + 2y

Simplifying
q = x + 2y

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