20(y+2)=4(4y+5)

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Solution for 20(y+2)=4(4y+5) equation: 


Simplifying
20(y + 2) = 4(4y + 5)

Reorder the terms:
20(2 + y) = 4(4y + 5)
(2 * 20 + y * 20) = 4(4y + 5)
(40 + 20y) = 4(4y + 5)

Reorder the terms:
40 + 20y = 4(5 + 4y)
40 + 20y = (5 * 4 + 4y * 4)
40 + 20y = (20 + 16y)

Solving
40 + 20y = 20 + 16y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-16y' to each side of the equation.
40 + 20y + -16y = 20 + 16y + -16y

Combine like terms: 20y + -16y = 4y
40 + 4y = 20 + 16y + -16y

Combine like terms: 16y + -16y = 0
40 + 4y = 20 + 0
40 + 4y = 20

Add '-40' to each side of the equation.
40 + -40 + 4y = 20 + -40

Combine like terms: 40 + -40 = 0
0 + 4y = 20 + -40
4y = 20 + -40

Combine like terms: 20 + -40 = -20
4y = -20

Divide each side by '4'.
y = -5

Simplifying
y = -5

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