20(y/5)=4y+3

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Solution for 20(y/5)=4y+3 equation: 



20(y/5)=4y+3

We move all terms to the left:

20(y/5)-(4y+3)=0

We add all the numbers together, and all the variables

20(+y/5)-(4y+3)=0

We multiply parentheses

20y-(4y+3)=0

We get rid of parentheses

20y-4y-3=0

We add all the numbers together, and all the variables

16y-3=0

We move all terms containing y to the left, all other terms to the right

16y=3

y=3/16

y=3/16

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