20(z+20)+15=6z-4

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Solution for 20(z+20)+15=6z-4 equation:



20(z+20)+15=6z-4
We move all terms to the left:
20(z+20)+15-(6z-4)=0
We multiply parentheses
20z-(6z-4)+400+15=0
We get rid of parentheses
20z-6z+4+400+15=0
We add all the numbers together, and all the variables
14z+419=0
We move all terms containing z to the left, all other terms to the right
14z=-419
z=-419/14
z=-29+13/14

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