20(z+30)=8-(-30z-40)

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Solution for 20(z+30)=8-(-30z-40) equation: 



20(z+30)=8-(-30z-40)

We move all terms to the left:

20(z+30)-(8-(-30z-40))=0

We multiply parentheses

20z-(8-(-30z-40))+600=0



We calculate terms in parentheses: -(8-(-30z-40)), so:

8-(-30z-40)

determiningTheFunctionDomain
-(-30z-40)+8

We get rid of parentheses

30z+40+8

We add all the numbers together, and all the variables

30z+48

Back to the equation:

-(30z+48)



We get rid of parentheses

20z-30z-48+600=0

We add all the numbers together, and all the variables

-10z+552=0

We move all terms containing z to the left, all other terms to the right

-10z=-552

z=-552/-10

z=55+1/5

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