20+(7n-5)+(7n-5)=38

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Solution for 20+(7n-5)+(7n-5)=38 equation: 



20+(7n-5)+(7n-5)=38

We move all terms to the left:

20+(7n-5)+(7n-5)-(38)=0

We add all the numbers together, and all the variables

(7n-5)+(7n-5)-18=0

We get rid of parentheses

7n+7n-5-5-18=0

We add all the numbers together, and all the variables

14n-28=0

We move all terms containing n to the left, all other terms to the right

14n=28

n=28/14

n=2

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