20+16+y=4(4y+5)

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Solution for 20+16+y=4(4y+5) equation: 



20+16+y=4(4y+5)

We move all terms to the left:

20+16+y-(4(4y+5))=0

We add all the numbers together, and all the variables

y-(4(4y+5))+36=0



We calculate terms in parentheses: -(4(4y+5)), so:

4(4y+5)

We multiply parentheses

16y+20

Back to the equation:

-(16y+20)



We get rid of parentheses

y-16y-20+36=0

We add all the numbers together, and all the variables

-15y+16=0

We move all terms containing y to the left, all other terms to the right

-15y=-16

y=-16/-15

y=1+1/15

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