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20+16x/4x=x
We move all terms to the left:
20+16x/4x-(x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-1x+16x/4x+20=0
We multiply all the terms by the denominator
-1x*4x+16x+20*4x=0
We add all the numbers together, and all the variables
16x-1x*4x+20*4x=0
Wy multiply elements
-4x^2+16x+80x=0
We add all the numbers together, and all the variables
-4x^2+96x=0
a = -4; b = 96; c = 0;
Δ = b2-4ac
Δ = 962-4·(-4)·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-96}{2*-4}=\frac{-192}{-8} =+24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+96}{2*-4}=\frac{0}{-8} =0 $
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