20+2(3x+10)=2(3+x)

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Solution for 20+2(3x+10)=2(3+x) equation: 



20+2(3x+10)=2(3+x)

We move all terms to the left:

20+2(3x+10)-(2(3+x))=0

We add all the numbers together, and all the variables

2(3x+10)-(2(x+3))+20=0

We multiply parentheses

6x-(2(x+3))+20+20=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

6x-(2x+6)+40=0

We get rid of parentheses

6x-2x-6+40=0

We add all the numbers together, and all the variables

4x+34=0

We move all terms containing x to the left, all other terms to the right

4x=-34

x=-34/4

x=-8+1/2

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