20+2(3x+10)=2-3(3+x)

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Solution for 20+2(3x+10)=2-3(3+x) equation: 



20+2(3x+10)=2-3(3+x)

We move all terms to the left:

20+2(3x+10)-(2-3(3+x))=0

We add all the numbers together, and all the variables

2(3x+10)-(2-3(x+3))+20=0

We multiply parentheses

6x-(2-3(x+3))+20+20=0



We calculate terms in parentheses: -(2-3(x+3)), so:

2-3(x+3)

determiningTheFunctionDomain
-3(x+3)+2

We multiply parentheses

-3x-9+2

We add all the numbers together, and all the variables

-3x-7

Back to the equation:

-(-3x-7)



We add all the numbers together, and all the variables

6x-(-3x-7)+40=0

We get rid of parentheses

6x+3x+7+40=0

We add all the numbers together, and all the variables

9x+47=0

We move all terms containing x to the left, all other terms to the right

9x=-47

x=-47/9

x=-5+2/9

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