20+2(3x+10)=2x-3(3+1x)

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Solution for 20+2(3x+10)=2x-3(3+1x) equation: 



20+2(3x+10)=2x-3(3+1x)

We move all terms to the left:

20+2(3x+10)-(2x-3(3+1x))=0

We add all the numbers together, and all the variables

2(3x+10)-(2x-3(x+3))+20=0

We multiply parentheses

6x-(2x-3(x+3))+20+20=0



We calculate terms in parentheses: -(2x-3(x+3)), so:

2x-3(x+3)

We multiply parentheses

2x-3x-9

We add all the numbers together, and all the variables

-1x-9

Back to the equation:

-(-1x-9)



We add all the numbers together, and all the variables

6x-(-1x-9)+40=0

We get rid of parentheses

6x+1x+9+40=0

We add all the numbers together, and all the variables

7x+49=0

We move all terms containing x to the left, all other terms to the right

7x=-49

x=-49/7

x=-7

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