20+2(3x+10)=2x-3(3-x)

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Solution for 20+2(3x+10)=2x-3(3-x) equation: 



20+2(3x+10)=2x-3(3-x)

We move all terms to the left:

20+2(3x+10)-(2x-3(3-x))=0

We add all the numbers together, and all the variables

2(3x+10)-(2x-3(-1x+3))+20=0

We multiply parentheses

6x-(2x-3(-1x+3))+20+20=0



We calculate terms in parentheses: -(2x-3(-1x+3)), so:

2x-3(-1x+3)

We multiply parentheses

2x+3x-9

We add all the numbers together, and all the variables

5x-9

Back to the equation:

-(5x-9)



We add all the numbers together, and all the variables

6x-(5x-9)+40=0

We get rid of parentheses

6x-5x+9+40=0

We add all the numbers together, and all the variables

x+49=0

We move all terms containing x to the left, all other terms to the right

x=-49

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