20+20=4x2

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Solution for 20+20=4x2 equation:



20+20=4x^2
We move all terms to the left:
20+20-(4x^2)=0
We add all the numbers together, and all the variables
-4x^2+40=0
a = -4; b = 0; c = +40;
Δ = b2-4ac
Δ = 02-4·(-4)·40
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{10}}{2*-4}=\frac{0-8\sqrt{10}}{-8} =-\frac{8\sqrt{10}}{-8} =-\frac{\sqrt{10}}{-1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{10}}{2*-4}=\frac{0+8\sqrt{10}}{-8} =\frac{8\sqrt{10}}{-8} =\frac{\sqrt{10}}{-1} $

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