20+3(x-5)=29

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Solution for 20+3(x-5)=29 equation: 



20+3(x-5)=29

We move all terms to the left:

20+3(x-5)-(29)=0

We add all the numbers together, and all the variables

3(x-5)-9=0

We multiply parentheses

3x-15-9=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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