20+3=1/2(6+4a)

Solution for 20+3=1/2(6+4a) equation:

20+3=1/2(6+4a)

We move all terms to the left:

20+3-(1/2(6+4a))=0


Domain of the equation: 2(6+4a))!=0

a∈R


We add all the numbers together, and all the variables

-(1/2(4a+6))+20+3=0

We add all the numbers together, and all the variables

-(1/2(4a+6))+23=0

We multiply all the terms by the denominator


-(1+23*2(4a+6))=0


We calculate terms in parentheses: -(1+23*2(4a+6)), so:

1+23*2(4a+6)

determiningTheFunctionDomain
23*2(4a+6)+1

Wy multiply elements

46a(4+1

Back to the equation:

-(46a(4+1)


We add all the numbers together, and all the variables

-(46a5=0