20+3x+2(x-3)=29

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Solution for 20+3x+2(x-3)=29 equation: 



20+3x+2(x-3)=29

We move all terms to the left:

20+3x+2(x-3)-(29)=0

We add all the numbers together, and all the variables

3x+2(x-3)-9=0

We multiply parentheses

3x+2x-6-9=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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