20+3x-4=11-(x*1)

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Solution for 20+3x-4=11-(x*1) equation: 



20+3x-4=11-(x*1)

We move all terms to the left:

20+3x-4-(11-(x*1))=0

We add all the numbers together, and all the variables

3x-(11-(+x*1))+20-4=0

We add all the numbers together, and all the variables

3x-(11-(+x*1))+16=0



We calculate terms in parentheses: -(11-(+x*1)), so:

11-(+x*1)

determiningTheFunctionDomain
-(+x*1)+11

We get rid of parentheses

-x*1+11

Wy multiply elements

-1x+11

Back to the equation:

-(-1x+11)



We get rid of parentheses

3x+1x-11+16=0

We add all the numbers together, and all the variables

4x+5=0

We move all terms containing x to the left, all other terms to the right

4x=-5

x=-5/4

x=-1+1/4

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